The difference between \( (n+1)^{\text {th }} \) Bohr radius and \( n^{\text {th }} \) Bohr....
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Question The difference between \( (n+1)^{\text {th }} \) Bohr radius and \( n^{\text {th }} \) Bohr radius is equal to the \( (n-1)^{\text {th }} \) Bohr radius. The value of \( n \) is
(A) 3
(B) 4
(C) 5
(D) 6📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live