The e.m.f. of the cell \( \mathrm{P} \) \( \mathrm{Zn}\left|\mathrm{Zn}^{2+}(0.01 \mathrm{M}) \|...
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0The e.m.f. of the cell
\( \mathrm{P} \) \( \mathrm{Zn}\left|\mathrm{Zn}^{2+}(0.01 \mathrm{M}) \| \mathrm{Fe}^{2+}(0.001 \mathrm{M})\right| \mathrm{Fe} \) at \( 298 \mathrm{~K} \) is
WW \( 0.2905 \) then the value of equilibrium constant for the cell reaction is
(1) \( \frac{0.32}{e^{0.0295}} \)
(2) \( 10^{\left(\frac{0.32}{0.0295}\right)} \)
(3) \( \frac{0.26}{10^{0.0295}} \)
(4) \( \frac{0.32}{10^{0.0591}} \)
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