The first I.P. of \( \mathrm{Al} \) is smaller than that of \( \mathrm{Mg} \) because: (A) atomi...
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0The first I.P. of \( \mathrm{Al} \) is smaller than that of \( \mathrm{Mg} \) because:
(A) atomic size of \( \mathrm{Al}\mathrm{Mg} \)
(B) \( \mathrm{Al} \) has one electron in \( p \)-orbital
(C) atomic size of \( \mathrm{Al}\mathrm{Mg} \)
(D) not known
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