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The formation of \( \mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-} \)is the basis for the formation of xenon fluorides. This is because
(a) \( \mathrm{O}_{2} \) and \( \mathrm{Xe} \) have comparable sizes
(b) both \( \mathrm{O}_{2} \) and \( \mathrm{Xe} \) are gases
(c) \( \mathrm{O}_{2} \) and \( \mathrm{Xe} \) have comparable ionisation energies
(d) Both (a) and (c)
\( \mathrm{P} \)
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