The formula of a gaseous hydrocarbon which requires 6 times of its own volume of \(\mathrm{O}_{2....

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The formula of a gaseous hydrocarbon which requires 6 times of its own volume of \(\mathrm{O}_{2}\) for complete oxidation and produces 4 times its own volume of \(\mathrm{CO}_{2}\) is \(\mathrm{C}_{\mathrm{x}} \mathrm{H}_{\mathrm{y}}\). The value of \(y\) is πŸ“²PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live



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