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The general solution of \( \sec \theta+\tan \theta=\sqrt{3} \) is
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(a) \( \theta=2 \mathrm{n} \pi+\frac{\pi}{6}, 2 \mathrm{n} \pi-\frac{\pi}{2}, \mathrm{n} \in \mathrm{I} \)
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(b) \( \theta=2 \mathrm{n} \pi+\frac{\pi}{6}, \mathrm{n} \in \mathrm{I} \)
(c) \( 2 \mathrm{n} \pi-\frac{\pi}{6}, \mathrm{n} \in \mathrm{I} \)
(d) \( 2 \mathrm{n} \pi-\frac{\pi}{2}, \mathrm{n} \neq 2 \mathrm{k}+1, \mathrm{n}, \mathrm{k} \in \mathrm{I} \)
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