The instantaneous angular position of a point on a rotating wheel is given by the equation \( \t...
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The instantaneous angular position of a point on a rotating wheel is given by the equation \( \theta(t)=2 t^{3}-6 t^{2} \). The torque on the wheel becomes zero at \( \quad \) [CBSE PMT (Pre.) 2011]
(a) \( t=2 \mathrm{~s} \)
(b) \( t=1 \mathrm{~s} \)
(c) \( t=0.2 \mathrm{~s} \)
(d) \( t=0.25 \mathrm{~s} \)
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