The integral \( \int\left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} d x \) is equal to.... VIDEO
The integral \( \int\left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} d x \) is equal to
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(1) \( (x+1) e^{x+\frac{1}{x}}+C \)
(2) \( -x e^{x+\frac{1}{x}}+C \)
(3) \( (x-1) e^{x+\frac{1}{x}}+C \)
(4) \( x e^{x+\frac{1}{x}}+C \)
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