The oxidation state of the most electronegative element in the products of the reaction between ...

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The oxidation state of the most electronegative element in the products of the reaction between \( \mathrm{BaO}_{2} \) and \( \mathrm{H}_{2} \mathrm{SO}_{4} \) are:
(A) 0 and \( -1 \)
(B) \( -1 \) and \( -2 \)
(C) \( -2 \) and 0
(D) \( -2 \) and \( +1 \)
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