The point \( \mathrm{P} \) on the ellipse \( 4 \mathrm{x}^{2}+9 \mathrm{x}^{2}=36 \) is such tha...
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0The point \( \mathrm{P} \) on the ellipse \( 4 \mathrm{x}^{2}+9 \mathrm{x}^{2}=36 \) is such that the area of the \( \Delta \mathrm{PF}_{1} \mathrm{~F}_{2}=\sqrt{10} \) where \( \mathrm{F}_{1}, \mathrm{~F}_{2} \) are foci. Then \( \mathrm{P} \) has the coordinates
(a) \( \left(\frac{3}{\sqrt{2}}, \sqrt{2}\right) \)
(b) \( \left(\frac{3}{2}, 2\right) \)
(c) \( \left(-\frac{3}{2},-2\right) \)
(d) \( \left(-\frac{3}{\sqrt{2}},-\sqrt{2}\right) \)
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