The position of a particle moving in a straight line is given by \[ x=3 t^{3}-18 t^{2}+36 t \] H...
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The position of a particle moving in a straight line is given by
\[
x=3 t^{3}-18 t^{2}+36 t
\]
Here, \( x \) is in \( m \) and \( t \) in second. Then
(A) direction of velocity and acceleration both change at \( t=2 \mathrm{~s} \)
(B) the distance travelled by particle is equal to magnitude of displacement for \( t=0 \) to \( t=5 \mathrm{~s} \)
(C) the speed of particle is decreasing in \( t=0 \) to \( t=2 \mathrm{~s} \) then it is increasing for \( t2 \)
(D) the magnitudes of velocity and acceleration are equal at \( t=0 \)
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