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The potential energy function for a particle executing linear SHM is given by \( V(x)=\frac{1}{2} k x^{2} \) where \( k \) is the force constant of the oscillator (Fig.) For \( k=0.5 \mathrm{~N} / \mathrm{m} \), the graph of \( V(x) \) versus \( x \) is shown in the figure. A particle of total energy \( E \) turns back when it reaches \( x=\pm x_{m} \). If \( V \) and \( K \) indicate the \( P E \) and \( K E \), respectively of the particle at \( x=+x_{m} \), then which of the following is correct
[NCERT Exemplar]
(a) \( V=0, \quad K=E \)
(b) \( V=E, \quad K=0 \)
(c) \( VE \quad K=0 \)
(d) \( V=0, \quad KE \)
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