The rate constant \( \mathrm{k}_{1} \) of a reaction is found to be double that of rate constant....
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Question The rate constant \( \mathrm{k}_{1} \) of a reaction is found to be double that of rate constant \( \mathrm{k}_{2} \) of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature \( \left(\mathrm{E}_{1} \& \mathrm{E}_{2}\right. \) ) can be represented as :
(A) \( \mathrm{E}_{1}>\mathrm{E}_{2} \)
(B) \( \mathrm{E}_{1}<\mathrm{E}_{2} \)
(C) \( \mathrm{E}_{1}=\mathrm{E}_{2} \)
(D) \( \mathrm{E}_{1}=4 \mathrm{E}_{2} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live