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The standard electrode potential for the following reaction is \( -0.57 \mathrm{~V} \). What is potential at \( \mathrm{pH}=12.0 ? \)
\( \mathrm{P} \)
\[
\mathrm{TeO}_{3}^{2-}(a q, 1 M)+3 \mathrm{H}_{2} \mathrm{O}(l)+4 e^{-} \longrightarrow \mathrm{Te}(s)+6 \mathrm{OH}^{-}(a q)
\]
(a) \( -0.17 \mathrm{~V} \)
(b) \( +0.21 \mathrm{~V} \)
(c) \( -0.39 \mathrm{~V} \)
(d) \( +1.95 \mathrm{~V} \)
W.
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