The sum of the series [JEE Main-2021 (February)] \( \sum_{n=1}^{\in...
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The sum of the series
[JEE Main-2021 (February)]
\( \sum_{n=1}^{\infty} \frac{n^{2}+6 n+10}{(2 n+1) !} \) is equal to :
\( \mathrm{P} \)
W)
(a) \( \frac{41}{8} e+\frac{19}{8} e^{-1}-10 \)
(b) \( \frac{41}{8} e-\frac{19}{8} e^{-1}-10 \)
(c) \( \frac{41}{8} e+\frac{19}{8} e^{-1}+10 \)
(d) \( -\frac{41}{8} e+\frac{19}{8} e^{-1}-10 \)
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