Duration: 3:53

277 views

0

The trajectory of a projectile in a vertical plane is
\( \mathrm{P} \) \( y=\alpha x-\beta x^{2} \), where \( \alpha \) and \( \beta \) are constants and \( x \& y \)

W. are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of A. . projection 8 and the maximum height attained \( \mathrm{H} \) are respectively given by:
[JEE Main-2021 (March)]
(a) \( \tan ^{-1} \alpha, \frac{\alpha^{2}}{4 \beta} \)
(b) \( \tan ^{-1} \alpha, \frac{4 \alpha^{2}}{\beta} \)
(c) \( \tan ^{-1}\left(\frac{\beta}{\alpha}\right), \frac{\alpha^{2}}{\beta} \)
(d) \( \tan ^{-1} \beta, \frac{\alpha^{2}}{2 \beta} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live