There are 3 copies each of 4 different books. The number of ways in which they can be arranged i...
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0There are 3 copies each of 4 different books. The number of ways in which they can be arranged in a shelf is
(A) \( \frac{12 !}{(3 ! 4} \)
(B) \( \frac{21 !}{(3 !)^{4} 4 !} \)
(C) \( \frac{12 !}{(4 !)^{3}} \)
(D) \( \frac{12 !}{(4 !)^{3} 3 !} \)
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