Duration: 6:13

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Call idiots idiots, but don't be hypocritical when you do.

My math:
If we assume the atmosphere supports a 1m thick ice sheet the atmosphere supporting it needs to be ~100mbar and the atmospheric pressure at sea level would be about ~10% thicker at sea level (1 atmosphere of pressure is equal to about 10m of water and ice is about 93% the density of water). Extrapolting from this graph:
http://www.physicalgeography.net/fundamentals/7d.html

We can see that the barostatic equilibrium altitude would be ~18 km
The amount of energy released from an object falling from said height would therefore be 18 km * 9.8 m/s^2 or 176.4 J/g. So one ton of ice would release about 1.764 x 10^8 J of energy.

The Titan I missile contained 100 tons of RP-1/LOX:
https://en.wikipedia.org/wiki/HGM-25A_Titan_I
RP-1 is a refined form of kerosene which is chiefly composed of 10-16 carbon alkanes. Dodecane (C12H26) make a good analogue. High molecular weight alkanes, like those found in RP-1 and kerosene have approximately equal mass specific energy densities.
Based on the enthalpy of combustion and molar mass of dodecane...:
https://en.wikipedia.org/wiki/Dodecane
I calculated a mass specific energy density of the combined bipropellant to be (enthalpy of combustion[7901kJ/mol]) / (molar mass of dodecane [762.34g/mol]+ mass of stoicheometric ratio of O2 [37 * 16g/mol])) ~ 10.37 kJ/g
Multiply this by mass of the rocket fuel (~ 10^8 g) to get ~ 10^12 joules (one terajoule).

1.037*10^12/(1.764*10^8) = 5878

The rocket is nearly 6000 times more energetic!