Two diameters of the circle \( 3 x^{2}+3 y^{2}-6 x-18 y-7=0 \) are ...

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Two diameters of the circle \( 3 x^{2}+3 y^{2}-6 x-18 y-7=0 \) are along the lines \( 3 x+y=c_{1} \) and \( x-3 y=c_{2} \). Then, the value
\( \mathrm{P} \) of \( c_{1} c_{2} \) is
(V)
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