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Two identical capacitors in parallel are charged with charge \( Q \) each. Separation of the plates in each capacitor is \( d_{0} \). Suddenly, the left plate of the first capacitor and the right plate of the second capacitor starts moving to the left with speed \( v \), then
(a) Charge on the two capacitor as a function of time are
\[
\frac{Q\left(d_{0}-v t\right)}{2 d_{0}}, \frac{Q\left(d_{0}+v t\right)}{2 d_{0}}
\]
(b) Charge on the two capacitors as a function of time are
\[
\frac{Q d_{0}}{2\left(d_{0}-v t\right)}, \frac{Q d_{0}}{2\left(d_{0}+v t\right)}
\]
(c) Current in the circuit will increase as time passes
(d) Current in the circuit will be constant
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