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Two parallel vertical metallic rails \( A B \) and \( C D \) are separated by \( 1 \mathrm{~m} \). They are connected at the two ends by resistance \( R_{1} \) and \( R_{2} \) as shown in the figure. A horizontal metallic bar \( L \) of mass \( 0.2 \mathrm{~kg} \) slides without friction, vertically down the rails under the action of gravity. There is a uniform horizontal magnetic field of \( 0.6 \mathrm{~T} \) perpendicular to the plane of the rails. It is observed that when the terminal velocity is attained, the power dissipated in \( R_{1} \) and \( R_{2} \) are \( 0.76 \mathrm{~W} \) and \( 1.2 \mathrm{~W} \) respectively. If the terminal velocity of bar \( L \) is \( x \mathrm{~m} / \mathrm{s} \) and \( R_{1} \) is \( y \Omega \) and \( R_{2} \) is \( z \Omega \) then find the value of \( x+76 y+10 z .\left(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\right) \).
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