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What is the equilibrium constant of the reaction: \( 2 \mathrm{Fe}^{3+}+\mathrm{Au}^{+} \rightarrow 2 \mathrm{Fe}^{2+}+\mathrm{Au}^{3+} \) ? Given \( E_{\mathrm{Au}^{+} \mid \mathrm{Au}}^{\circ}=1.68 \) \( \mathrm{V}, E_{\mathrm{Au}^{3+} \mid \mathrm{Au}}^{\circ}=1.50 \mathrm{~V}, E_{\mathrm{Fe}^{3+} \mid \mathrm{Fe}^{2+}}^{\circ}=0.75 \mathrm{~V} \) and \( 2.303 \) \( R T / F=0.06 \).
(a) \( 1 \times 10^{22} \)
(b) \( 1 \times 10^{-22} \)
(c) \( 1 \times 10^{-11} \)
(d) \( 1 \times 10^{-72} \)
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