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When \( \mathrm{XeF}_{2} \) and \( \mathrm{XeF}_{6} \) are separately hydrolysed then;
(a) both give out \( \mathrm{O}_{2} \)
(b) \( \mathrm{XeF}_{6} \) gives \( \mathrm{O}_{2} \) and \( \mathrm{XeF}_{2} \) does not
\( \mathrm{P} \)
(c) \( \mathrm{XeF}_{2} \) alone gives \( \mathrm{O}_{2} \)
(d) Neither of them gives \( \mathrm{HF} \)
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