X-rays of wavelength \( \lambda \) fall on a photosensitive surface, emitting electrons. Assum...
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X-rays of wavelength \( \lambda \) fall on a photosensitive surface, emitting electrons. Assuming that the work function of the surface can be neglected, prove that de Broglie of electrons emitted will be \( \sqrt{\frac{h \lambda}{2 m c}} \).
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