| 2023-01-04 | major contribution of Sir CV raman is in | 0:36 | 9 | |
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| 2023-01-04 | if time is homogeneous energy law of conservation is | 0:31 | 4 | |
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| 2023-01-04 | basic reason behind the existence of conservation of law could not find | 0:41 | 4 | |
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| 2023-01-04 | The gravitational force between any two charged bodies with the distance as F directly proportional | 0:44 | 4 | |
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| 2023-01-04 | Mathematical induction is the principle containing the set | 0:31 | 9 | |
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| 2023-01-04 | (n factorial)^2 is greater than equal to n^n is true for | 0:59 | 5 | |
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| 2023-01-04 | for all n belongs to N ,1+1/root 2+1/root 3+1/root 4+..+1/root n | 0:32 | 6 | |
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| 2023-01-04 | 1 cube+2 cube+3 cube +......+100 cube=k square then k= | 0:46 | 7 | |
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| 2023-01-04 | 4 cube+8 cube+12 cube +......to n terms = | 0:51 | 6 | |
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| 2023-01-04 | 1.3+3.5+5.7 +....n terms = | 0:58 | 4 | |
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| 2023-01-04 | x^2n+y^2n need not be divisible by x+y if n is | 0:42 | 5 | |
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| 2023-01-04 | if n belongs to N ,n is odd then n(n^2-1) is divisible by | 0:34 | 5 | |
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| 2023-01-04 | if 1+1/1+2+1/1+2+3+....+1/1+2+3+4+..+n=kn/n+1 for all n belongs N,then k= | 0:34 | 4 | |
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| 2023-01-04 | The value of the sum in the nth bracket of (1)+(2+3+4)+(5+6+7+8+9)+... | 0:42 | 23 | |
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| 2023-01-04 | (1-1/2)(1-1/3)(1-1/4)......(1-1/n+1)= | 0:55 | 6 | |
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| 2023-01-04 | 1+3+6+.....+n(n+1)/2= | 0:58 | 5 | |
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| 2023-01-04 | Sum of first n terms of the series 3/2+5/4+9/8+17/16+...... | 0:38 | 17 | |
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| 2023-01-04 | The sum of n terms of the series 2+8+14 +.... | 0:56 | 4 | |
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| 2023-01-04 | (1^2)+(1^2+2^2)+(1^2+2^2+3^2)+...n brackets | 0:49 | 4 | |
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| 2023-01-04 | The statement p(n)=9^n-8^n when divisible by 8 always leaves the remainder | 0:28 | 5 | |
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| 2023-01-04 | Every even power of every odd number greater than 1 when divided by 8 leaves the remainder | 0:44 | 18 | |
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| 2023-01-04 | If a,b,c belongs to N,a^n+b^n is divisible by c when n is odd but not when n is even,then the value | 0:34 | 8 | |
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| 2023-01-04 | If the sum of n terms of an A.P. is 4n^2-3n/4 then nth term of the A.P. is | 0:52 | 4 | |
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| 2023-01-04 | x^2n-1+y^2n-1 is divisible by x+y if n is | 0:42 | 14 | |
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| 2023-01-04 | the nth term of the series 3+7+13+21+.....is | 1:41 | 0 | |
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| 2023-01-04 | 3n^5+5n^3+7n is divisible by ....for all n belongs to N | 0:37 | 12 | |
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| 2023-01-04 | For all positive integral values of n ,3^2n+7 is divisible by | 0:32 | 29 | |
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| 2023-01-04 | for all n belongs to N,2.4^2n+1+3^3n+1 is divisible by | 0:31 | 8 | |
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| 2023-01-04 | if 49^n +16n+k is divisible by 64 for n belongs to N ,then K | 0:43 | 6 | |
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| 2023-01-04 | statement 1:if x less than 1,submision (-1)^n x^n+1=x/1+x, statement 2:(1+x)^-1=1-x+x^2-x^3+... | 0:48 | 5 | |
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| 2023-01-04 | 2+3+5+6+8+9+...2n terms = | 0:40 | 15 | |
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| 2023-01-04 | 1/1.3+1/3.5+1/5.7+....+n(n-3) terms | 1:00 | 21 | |
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| 2023-01-04 | 1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+...upto 20 terms is | 0:48 | 4 | |
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| 2023-01-04 | Submmission 1^2+2^2+3^2+...+n^2/1+2+3+..+n= | 0:49 | 4 | |
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| 2023-01-04 | if p(n):1+3+5+....+(2n-1)=n^2 is | 0:41 | 4 | |
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| 2023-01-04 | if p(n):1+3+5+...+(2n-1)=n^2 is | 0:18 | 4 | |
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| 2023-01-04 | (n+2)factorial/(n-1)factorial is divisible by | 0:40 | 7 | |
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| 2023-01-04 | 2.4+4.7+6.10+...(n-1)terms= | 0:42 | 34 | |
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| 2023-01-04 | sum to n terms of the series 1+3+7+15+....is | 0:38 | 5 | |
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| 2023-01-04 | 2023 01 04 14 25 33 | 0:44 | 8 | |
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| 2023-01-04 | 3/4+15/16+63/64+...n terms= | 0:37 | 4 | |
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| 2023-01-04 | for n belong to N,1/5 n^5+1/3 n^3+7/15 n is | 0:44 | 4 | |
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| 2023-01-04 | the value of the sum in the nth brackets of (1)+(2+3)+(4+5+6+7)+(8+9+10+..+15)+..is | 0:50 | 10 | |
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| 2023-01-04 | submmission from n to r=1(3^r-r)= | 1:00 | 4 | |
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| 2023-01-04 | Submmission from n to r=1 (3^r-r)= | 0:41 | 4 | |
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| 2023-01-04 | 2023 01 04 14 06 48 | 0:15 | 4 | |
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| 2023-01-04 | 3^2n+2^3.n-9 is divisible by | 0:26 | 6 | |
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| 2023-01-04 | the inequality n factorial greater than 2^n-1 is true | 0:38 | 4 | |
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| 2023-01-04 | for all n belong to N,n^2(n^4-1)is divisible by | 0:30 | 4 | |
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| 2023-01-04 | 2023 01 04 14 46 53 | 0:17 | 4 | |
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| 2023-01-04 | Statement 1:for all +ve integrals value of n 3^2n+7 is divisible by 8,2:G.C.F 16 and 88 is 8 | 0:33 | 5 | |
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| 2023-01-04 | If ak=1/k(k+1) for k=1,2,3....n then submission of (ak)^2=n^2/(n+1)^2,sum of the n terms of a | 0:39 | 18 | |
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| 2023-01-04 | Statement 1:n belongs to N product of n(n+1)(n+2) is divisible by 6,2:product of 3 consecutive | 0:50 | 4 | |
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| 2023-01-04 | statement 1:for all n belongs to N,x^(2n+1)+y^(2n+1) is divisible by x+y,2:if n belongs to N, | 0:42 | 5 | |
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| 2023-01-04 | 1.3+2.3^2+3.3^3+.....+n.3^n= | 0:25 | 4 | |
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| 2023-01-04 | 1.2^2+2.3^2+3.4^2+...+n(n+1)^2= | 0:45 | 10 | |
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| 2023-01-04 | 1.2^2+2.3^2+3.4^2+...+n(n+1)^2= | 0:17 | 4 | |
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| 2023-01-04 | 1.3.4+2.4.5+3.5.6+n terms = | 0:39 | 8 | |
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| 2023-01-04 | The value of the sum in the 10th bracket of(1)+(2+3+4)+(5+6+7+8+9)+... | 0:49 | 4 | |
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| 2023-01-04 | the greatest positive integers which divides (n+1)(n+2)(n+3)...(n+r)for all n belongs to N is | 0:29 | 8 | |
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| 2023-01-04 | The sum of the cubes of 3 successive natural numbers is divisible by | 0:32 | 7 | |
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| 2023-01-03 | JEE Questions for practice 2 | 26:31 | 15 | |
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| 2023-01-03 | MCQ JEE 2023 | 38:58 | 7 | |
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| 2023-01-03 | The ratio in which the line segment joining the points (2,-4,3) and (-4,5,-6) is divisible by xy | 0:49 | 6 | |
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| 2023-01-03 | the 1st point of trisection of segment joining (3,-1,2) and (9,5,2) is | 0:52 | 17 | |
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| 2023-01-03 | The points A(5,-1,1),B( 7,-4,7),C(1,-6,10),D(-1,-3,4) form | 0:58 | 4 | |
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| 2023-01-03 | The points A(3,4,5),B(2,3,1),C(-1,6,1) form | 0:50 | 6 | |
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| 2023-01-03 | two opposite vertices of a square are (2,-3,4) and (4,1,-2).the length of the side of the square is | 0:50 | 6 | |
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| 2023-01-03 | If A,B are the feet of the perpendiculars from P(2,4,5)to the x axis and y axis respectively | 0:50 | 9 | |
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| 2023-01-03 | the number of octants in which z coordinate is positive in | 0:37 | 7 | |
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| 2023-01-03 | the incenter of triangle ABC with vertices A(0,0,0),B(0,3,0),C(4,0,0) is | 0:40 | 23 | |
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| 2023-01-03 | in the orthocenter and the circumcenter of the triangle are (-3,5,2),(6,2,5),then its centeroid is | 0:48 | 7 | |
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| 2023-01-03 | The circumradius of triangle ABC with vertices A(2,-1,1),B(1,-3,-5),C(3,-4,4) is | 0:53 | 29 | |
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| 2023-01-03 | The circumcenter of the triangle formed by the points (1,2,3),(3,1,2),(2,3,1) is | 0:39 | 12 | |
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| 2023-01-03 | Let A(4,7,8),B(2,3,4)and C(2,5,7)be the vertices of triangle ABC .the length of the median AD is | 0:52 | 10 | |
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| 2023-01-03 | The point P is on the y axis .if P is equidistant from (1,2,3) and (2,3,4),then P3= | 1:31 | 0 | |
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| 2023-01-03 | If L,M are the feet of the perpendicular from the (2,4,5) to the xy-plane and yz-plane respectively. | 1:19 | 8 | |
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| 2023-01-03 | The points A(-1,0,7),B(3,2,1),C(5,3,-2) are collinear then the ratio in which C divides AB is | 1:03 | 0 | |
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| 2023-01-03 | If the perpendicular distances from the point P to the coordinate axes are 2,3,5 the distance | 1:32 | 1 | |
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| 2023-01-03 | The ratio in which the line joining the points (3,3,1) and (6,-6,-2) is divided by the x-axis is | 0:47 | 6 | |
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| 2023-01-03 | The point which divides the line segment joining the points (3,2,5) and (4,-1,3) in the ratio 2:3 is | 0:39 | 7 | |
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| 2023-01-03 | The transformed equation of 2x^2+3y^2-z^2-8x+18y+2z+9=0 when the axis are translated to the point | 0:58 | 6 | |
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| 2023-01-03 | 2023 01 03 16 28 50 | 0:13 | 11 | |
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| 2023-01-03 | The distance between origin and (sinx,cosx,1)is | 0:45 | 5 | |
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| 2023-01-03 | if points (1,-1,-5),(3,1,3) and (9,1,-3)form | 0:46 | 5 | |
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| 2023-01-03 | the points A(2,9,12),B(1,8,8),C(-2,11,8) and D(-1,12,12) form | 0:59 | 6 | |
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| 2023-01-03 | The ratio in which the line segment joining (-2,3,1),(3,5,2) is divided by yz plane is | 0:48 | 5 | |
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| 2023-01-03 | If (4,2,p) is the centroid of the tetraheadron formed by the points (k,2,-1),(4,1,1),(6,2,5), | 0:49 | 5 | |
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| 2023-01-03 | The origin is the centroid of the triangle for which (-2,3,4),(3,-1,5) are two vertices,then the 3 | 1:00 | 5 | |
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| 2023-01-03 | If (2,k,-1) is the centroid of the triangle with vertices (2,-1,2),(1,-3,-4)and (3,k,1) ,then k= | 0:43 | 5 | |
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| 2023-01-03 | in triangle ABC, D,E,F are the mid points of the sides BC,CA,AB respectively,A(2,3,4),D(1,-4,2) | 0:48 | 5 | |
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| 2023-01-03 | If (k,1,5),(1,0,3) and (7,-2,l) are collinear points then 2k+3l = | 0:53 | 6 | |
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| 2023-01-03 | If A (1,0,1),B(3,4,5),C(0,-1,2)are 3 consecutive vertices of a parallelogram then the 4th vertex | 0:55 | 5 | |
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| 2023-01-03 | The distance between the origin and the centroid of the tetrahedron whose vertices are (0,0,0) | 0:40 | 10 | |
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| 2023-01-03 | If the centroid of the tetrahedron is (0,-1,5/2) and 3 vertices are(-2,3,4)(3,-4,2)(2,-5,1)then the | 0:59 | 10 | |
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| 2023-01-03 | The coordinates of the point equidistant from the 4 points(a,0,0)(0,b,0)(0,0,c)(0,0,0) are | 0:52 | 6 | |
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| 2023-01-03 | the distance between the circumcenter and the orthocenter of ABC with vertices A(2,1,5)B(3,2,3) | 0:48 | 7 | |
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| 2023-01-03 | If(1,2,3)(2,3,1)are two vertices of an equilateral triangle then its 3rd vertex is | 0:49 | 6 | |
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| 2023-01-03 | The incenter of triangle ABC with vertices A(0,0,4),B(3,0,4),C(0,4,4) is | 0:40 | 5 | |
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| 2023-01-03 | The points (a,b,c),(b,c,a),(c,a,b) are the vertices of | 0:37 | 7 | |
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