the nth term of the series 3+7+13+21+.....is

Channel:
India Flame Institute
Subscribers:
4,220
Published on ● Video Link: https://www.youtube.com/watch?v=zXsyz6HgLig


Duration: 1:41
0 views
0

< no description available >



Other Videos By Flame Institute


2023-01-04(1-1/2)(1-1/3)(1-1/4)......(1-1/n+1)=
2023-01-041+3+6+.....+n(n+1)/2=
2023-01-04Sum of first n terms of the series 3/2+5/4+9/8+17/16+......
2023-01-04The sum of n terms of the series 2+8+14 +....
2023-01-04(1^2)+(1^2+2^2)+(1^2+2^2+3^2)+...n brackets
2023-01-04The statement p(n)=9^n-8^n when divisible by 8 always leaves the remainder
2023-01-04Every even power of every odd number greater than 1 when divided by 8 leaves the remainder
2023-01-04If a,b,c belongs to N,a^n+b^n is divisible by c when n is odd but not when n is even,then the value
2023-01-04If the sum of n terms of an A.P. is 4n^2-3n/4 then nth term of the A.P. is
2023-01-04x^2n-1+y^2n-1 is divisible by x+y if n is
2023-01-04the nth term of the series 3+7+13+21+.....is
2023-01-043n^5+5n^3+7n is divisible by ....for all n belongs to N
2023-01-04For all positive integral values of n ,3^2n+7 is divisible by
2023-01-04for all n belongs to N,2.4^2n+1+3^3n+1 is divisible by
2023-01-04if 49^n +16n+k is divisible by 64 for n belongs to N ,then K
2023-01-04statement 1:if x less than 1,submision (-1)^n x^n+1=x/1+x, statement 2:(1+x)^-1=1-x+x^2-x^3+...
2023-01-042+3+5+6+8+9+...2n terms =
2023-01-041/1.3+1/3.5+1/5.7+....+n(n-3) terms
2023-01-041+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+...upto 20 terms is
2023-01-04Submmission 1^2+2^2+3^2+...+n^2/1+2+3+..+n=
2023-01-04if p(n):1+3+5+....+(2n-1)=n^2 is