\( 10 \mathrm{~mL} \) of \( \mathrm{H}_{2} \mathrm{O}_{2} \) solution is treated with \( \mathrm...
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\( 10 \mathrm{~mL} \) of \( \mathrm{H}_{2} \mathrm{O}_{2} \) solution is treated with \( \mathrm{KI} \) and titration of liberated \( \mathrm{I}_{2} \) required \( 10 \mathrm{~mL} \) of \( 1 \mathrm{~N} \mathrm{hypo} \). Thus \( \mathrm{H}_{2} \mathrm{O}_{2} \) is
(A) \( 1 \mathrm{~N} \)
(B) \( 5.6 \) volume
(C) \( 17 \mathrm{gL}^{-1} \)
(D) all are correct
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