A block of mass \( 1 \mathrm{~kg} \) slides down on a rough inclined plane of inclination \( 60^...
Channel:
Subscribers:
443,000
Published on ● Video Link: https://www.youtube.com/watch?v=D3TmKIrJTjg
A block of mass \( 1 \mathrm{~kg} \) slides down on a rough inclined plane of inclination \( 60^{\circ} \) starting from its top. If the coefficient of kinetic friction is \( 0.5 \) and length of the plane is \( 1 \mathrm{~m} \), then work done against friction is (Take \( g=9.8 \mathrm{~m} / \mathrm{s}^{2} \) )
[AFMC 2000; KCET 2001]
(a) \( 9.82 \mathrm{~J} \)
(b) \( 4.94 \mathrm{~J} \)
(c) \( 2.45 \mathrm{~J} \)
(d) \( 1.96 \mathrm{~J} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw