A force acts on a \( 30 \mathrm{~g} \) particle in such a way that the position of the particle ...
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A force acts on a \( 30 \mathrm{~g} \) particle in such a way that the position of the particle as a function of time is given by \( x=3 t-4 t^{2}+t^{3} \), where \( x \) is in metres and \( t \) is in seconds. The work done during the first 4 seconds is
[CBSE PMT 1998; Similar Kerala PET 2012]
(a) \( 5.28 \mathrm{~J} \)
(b) \( 450 \mathrm{~mJ} \)
(c) \( 490 \mathrm{~mJ} \)
(d) \( 530 \mathrm{~mJ} \)
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