A body is projected vertically upward with speed 40 \( \mathrm{P} \...

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A body is projected vertically upward with speed 40
\( \mathrm{P} \) \( \mathrm{m} / \mathrm{s} \). The distance travelled by body in the last second of upward journey is [take \( g=9.8 \mathrm{~m} / \mathrm{s}^{2} \) and neglect
W. effect of air resistance]
(1) \( 4.9 \mathrm{~m} \)
(2) \( 9.8 \mathrm{~m} \)
(3) \( 12.4 \mathrm{~m} \)
(4) \( 19.6 \mathrm{~m} \)
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