A foot of the normal from the point \( (4,3) \) to a circle is \( (2,1) \) and a diameter of the...

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A foot of the normal from the point \( (4,3) \) to a circle is \( (2,1) \) and a diameter of the circle has the equation \( 2 x-y=2 \). Then the equation of the circle is
(a) \( x^{2}+y^{2}+2 x-1=0 \)
(b) \( x^{2}+y^{2}-2 x-1=0 \)
(c) \( x^{2}+y^{2}-2 y-1=0 \)
(d) none of these
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