The members of a family of circles are given by the equation \( 2\left(x^{2}+y^{2}\right)+\lambd...

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The members of a family of circles are given by the equation \( 2\left(x^{2}+y^{2}\right)+\lambda x-\left(1+\lambda^{2}\right) y-10=0 \). The number of circles belonging to the family that are cut orthogonally by the fixed circle \( x^{2}+y^{2}+ \) \( 4 x+6 y+3=0 \) is
(a) 2
(b) 1
(c) 0
(d) none of these
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