A force acts on a \( 30 \mathrm{~g} \) particle in such a way that the position of the particle ....
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Question A force acts on a \( 30 \mathrm{~g} \) particle in such a way that the position of the particle as a function of time is given by \( x=3 t-4 t^{2}+t^{3} \), where \( \mathrm{x} \) is in metres and \( t \) is in seconds. The work done during the first 4 second is
(A) \( 5.28 \mathrm{~J} \)
(B) \( 450 \mathrm{~J} \)
(C) \( 490 \mathrm{~mJ} \)
(D) \( 530 \mathrm{~mJ} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live