A free electron of \( 2.6 \mathrm{eV} \) energy collides with a \( \mathrm{H}+ \) ion. This resu...
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A free electron of \( 2.6 \mathrm{eV} \) energy collides with a \( \mathrm{H}+ \) ion. This results in the formation of a hydrogen atom
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in the first excited state and a photon is released. Find
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the frequency of the emitted photon. \( \left(\mathrm{h}=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s}\right) \)
(1) \( 9.0 \times 10^{27} \mathrm{MHz} \)
(2) \( 1.45 \times 10^{9} \mathrm{MHz} \)
(3) \( 0.19 \times 10^{15} \mathrm{MHz} \)
(4) \( 1.45 \times 10^{11} \mathrm{MHz} \)
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