A helium nucleus makes a full rotation in a circle of radius \( 0.8 \) metre in two seconds. The...
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A helium nucleus makes a full rotation in a circle of radius \( 0.8 \) metre in two seconds. The value of the
\( \mathrm{P} \) magnetic field \( B \) at the centre of the circle will be
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(1) \( \frac{10^{-19}}{\mu_{0}} \)
(2) \( 10^{-19} \mu_{0} \)
(3) \( 2 \times 10^{-10} \mu_{0} \)
(4) \( \frac{2 \times 10^{-10}}{\mu_{0}} \)
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