A magnetic needle lying parallel to magnetic field requires \( \mat...

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A magnetic needle lying parallel to magnetic field requires \( \mathrm{W} \) unit of work to turn it through \( 60^{\circ} \). The torque needed to maintain the needle in this final position will be
(1) \( \sqrt{3} W \)
(2) \( \mathrm{W} \)
(3) \( \frac{\sqrt{3} W}{2} \)
(4) \( 2 \mathrm{~W} \)
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