A man is standing on the top of a building \( 100 \mathrm{~m} \) high. He throws two stones vert... VIDEO
A man is standing on the top of a building \( 100 \mathrm{~m} \) high. He throws two stones vertically, one at \( t=0 \) and other after a time interval (less than \( 2 \mathrm{~s} \) ). The later stone is thrown at a velocity of half the first. The vertical gap between first and second stone is \( 15 \mathrm{~m} \) at \( t=2 \mathrm{~s} \). The gap is found to remain constant. The velocities with which the stones were thrown are \( \left(\right. \) take \( \left.g=10 \mathrm{~ms}^{-2}\right) \)
(a) \( 20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1} \)
(b) \( 10 \mathrm{~ms}^{-1}, 5 \mathrm{~ms}^{-1} \)
(c) \( 16 \mathrm{~ms}^{-1}, 8 \mathrm{~ms}^{-1} \)
(d) \( 30 \mathrm{~ms}^{-1}, 15 \mathrm{~ms}^{-1} \)
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