If the velocity of a particle is \( v=A t+B t^{2} \), where \( A \) and \( B \) are constants, t...

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If the velocity of a particle is \( v=A t+B t^{2} \), where \( A \) and \( B \) are constants, then the distance travelled by it between \( 1 \mathrm{~s} \) and \( 2 \mathrm{~s} \) is
(a) \( 3 A+7 B \)
(b) \( \frac{3}{2} A+\frac{7}{3} B \)
(c) \( \frac{A}{2}+\frac{B}{3} \)
(d) \( \frac{3}{2} A+4 B \)
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