A man measures the period of a simple pendulum inside a stationary ...
Channel:
Subscribers:
447,000
Published on ● Video Link: https://www.youtube.com/watch?v=_XZ-29IF3d4
A man measures the period of a simple pendulum inside a stationary lift and finds it to be \( T \mathrm{~s} \). If the lift accelerates
\( \mathrm{P} \) upwards with an acceleration \( g / 4 \), then the period of the pendulum will be
[NCERT 1990; BHU 2001;
W
DPMT 2000, 03; Kerala PET 2008]
(a) \( T \)
(b) \( \frac{T}{4} \)
(c) \( \frac{2 T}{\sqrt{5}} \)
(d) \( 2 T \sqrt{5} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw