Duration: 8:35

4 views

0

A parallel plate capacitor of plate area \( A \) and separation \( d \) is charged to a potential difference \( V \) and then battery is disconnected. A slab of dielectric constant \( K \) is then inserted between the plates so as to fill space between the plates. If \( Q_{1} E_{1} W \) denote charge on each plate, electric field
between the plates and work done on the system respectively, in the process of inserting the slab then :
(a) \( Q=\frac{\epsilon_{0} A V}{d} \)
(b) \( Q=\frac{\epsilon_{0} K A V}{d} \)
(c) \( E=\frac{V}{K d} \)
(d) \( W=\frac{\epsilon_{0} A V^{2}}{2 d}\left(1-\frac{1}{K}\right) \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live