A particle is projected at an angle \( 60^{\circ} \) with horizontal with a speed of \( 10 \sqrt...

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A particle is projected at an angle \( 60^{\circ} \) with horizontal with a speed of \( 10 \sqrt{3} \mathrm{~m} / \mathrm{s} \) from point \( A \) as shown. At the same time the sufficient long wedge is made to move with constant velocity of \( 10 \sqrt{3} \) towards right as shown in figure-1.137. The time in second after which particle will hit the wedge will be. \( \left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right) \).
(A) \( 1 \mathrm{sec} \)
(B) \( 2 \mathrm{sec} \)
(C) 3 sec
(D) it will never collide on the wedgé
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