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Question A particle is projected with velocity \( v_{0} \) along x-axis.A damping force is acting on the particle which is proportional to the square of the square of the distance from the origin i.e., \( m a=-\alpha x^{2} \). The distance at which the particle stops.
(A) \( \left(\frac{3 m v_{0}^{2}}{2 \alpha}\right)^{\frac{1}{2}} \)
(B) \( \left(\frac{2 m v_{0}}{3 \alpha}\right)^{\frac{1}{3}} \)
(C) \( \left(\frac{2 m v_{0}^{2}}{3 \alpha}\right)^{\frac{1}{2}} \)
(D) \( \left(\frac{3 m v_{0}^{2}}{2 \alpha}\right)^{\frac{1}{3}} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live