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A particle moving in a circle of radius \( \mathrm{R} \). with a uniform speed takes a time \( T \) to complete one revolution. If this particle were projected with the same speed at an angle ' \( \theta \) ' to the horizontal, the maximum height attained by it equals \( 4 \mathrm{R} \). The angle of projection, \( \theta \), is then given by :
(a) \( \theta=\sin ^{-1}\left(\frac{2 g T^{2}}{\pi^{2} R}\right)^{1 / 2} \)
(b) \( \theta=\cos ^{-1}\left(\frac{g T^{2}}{\pi^{2} R}\right)^{1 / 2} \)
(c) \( \theta=\cos ^{-1}\left(\frac{\pi^{2} R}{g T^{2}}\right)^{1 / 2} \)
(d) \( \theta=\sin ^{-1}\left(\frac{\pi^{2} R}{g T^{2}}\right)^{1 / 2} \)
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