A particle starting from rest, moves in a circle of radius ' \( r \...
Channel:
Subscribers:
451,000
Published on ● Video Link: https://www.youtube.com/watch?v=lrYvsGrSTow
A particle starting from rest, moves in a circle of radius ' \( r \) '. It attains a velocity of \( V_{0} \mathrm{~m} / \mathrm{s} \) in the \( n^{\text {th }} \)
\( \mathrm{P} \) round. Its angular acceleration will be
W
(1) \( \frac{V_{0}}{n} \mathrm{rad} / \mathrm{s}^{2} \)
(2) \( \frac{V_{0}}{2 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2} \)
(3) \( \frac{V_{0}^{2}}{4 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2} \)
(4) \( \frac{V_{0}^{2}}{4 \pi n r} \mathrm{rad} / \mathrm{s}^{2} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw