A point \( (2,1) \) is outside the circle \( x^{2}+y^{2}+2 g x+2 f ...
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A point \( (2,1) \) is outside the circle \( x^{2}+y^{2}+2 g x+2 f y+c=0 \) and AP, AQ are tangents to the circle. The equation of the circle circumscribing the triangle APQ is
\( \mathrm{P} \)
(A) \( (x+g)(x-2)+(y+f)(y-1)=0 \)
(B) \( (x+g)(x-2)-(y+f)(y-1)=0 \)
(C) \( (x-g)(x+2)+(y-f)(y+1)=0 \)
(D) none
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