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A point mass \( m \) is placed at the centre of the square \( A B C D \) of side \( a \) units as shown below.

The resultant gravitational force on mass \( m \) due to masses \( m_{1} \) and \( m_{2} \) placed on the vertices of square is
(a) \( \frac{G m_{1} m_{2}}{(a \sqrt{2})^{2}} \)
(b) \( \frac{2 G m\left(m_{1}+m_{2}\right)}{a^{2}} \)
(c) zero
(d) \( \frac{G m\left(m_{1}+m_{2}\right)}{(a \sqrt{2})^{2}} \)
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