Duration: 7:37

1 views

0

A projectile is projected with velocity of \( 25 \mathrm{~m} / \mathrm{s} \) at an angle \( \theta \) with the horizonal. After \( t \) seconds its inclination with horizontal becomes zero. If \( R \) represents horizontal range of the projectile, the value of \( \theta \) will be [use \( g=10 \mathrm{~m} / \mathrm{s}^{2} \) ]
(a) \( \frac{1}{2} \sin ^{-1}\left(\frac{5 t^{2}}{4 R}\right) \)
(b) \( \frac{1}{2} \sin ^{-1}\left(\frac{4 R^{2}}{5 t^{2}}\right) \)
(c) \( \tan ^{-1}\left(\frac{4 t^{2}}{5 R}\right) \)
(d) \( \cot ^{-1}\left(\frac{R}{20 t^{2}}\right) \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live