Duration: 4:10

767 views

0

A square loop made of 4 identical conducting rods each of mass \( m \) and length 1 carry current \( i \).
The loop is placed in a vertical position on a frictionless horizontal plane. A uniform horizontal magnetic field \( \mathrm{B}_{0} \) is in the plane of the loop, then find the torque due to magnetic field on the loop at this instant:
(1) Zero
(2) \( i 1^{2} B_{0} \)
(3) \( \frac{\mathrm{il}^{2} \mathrm{~B}_{0}}{2} \)
(4) \( 2 \mathrm{il}^{2} \mathrm{~B}_{0} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live