Duration: 3:23

6 views

0

A thin uniform circular tube is kept in a vertical plane. Equal volumes of two immiscible liquids whose densities are \( \rho_{1} \) and \( \rho_{2} \) fill half of the tube as shown. In equilibrium the radius passing through the interface makes an angle of \( 30^{\circ} \) with vertical. The ratio of densities \( \left(\rho_{1} / \rho_{2}\right) \) is equal to
(a) \( \frac{\sqrt{3}-1}{2-\sqrt{3}} \)
(b) \( \frac{\sqrt{3}+1}{2+\sqrt{3}} \)
(c) \( \frac{\sqrt{3}-1}{\sqrt{3}+1} \)
(d) \( \frac{\sqrt{3}+1}{\sqrt{3}-1} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live