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A U-shaped wire of mass \( m \) and length/ is immersed with its two ends in mercury (see figure). The wire is in a homogeneous field of magnetic induction \( \mathbf{B} \). If a charge, that is, a current pulse \( \mathrm{q}=\int \mathrm{idt} \), is sent through the wire, the wire will jump up.
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V Calculate, the height \( h \) that the wire reaches, the size of the charge or current pulse, assuming that - the time of the current pulse is very small in comparision with the time of flight. Make use of the fact - that impulse of force equals \( \int \mathrm{Fdt} \), which equals mv. Evaluate \( \mathrm{q} \mathrm{for} \mathrm{B}=0.1 \mathrm{~Wb} / \mathrm{m}^{2}, \mathrm{~m}=10 \mathrm{gm} \), \( -\ell=20 \mathrm{~cm} \& \mathrm{~h}=3 \) meters. \( \left[\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right] \)
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